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## Homework Statement

Consider a particle of mass m and a particle of mass 2m. They are connected by a horizontal, massless, rigid rod of length 2a. The rod is fixed to a vertical stick that connects to the rod's midpoint. The stick is spinning with constant angular speed.

Consider a point P, located on the stick a distance d below the rod. Show that angular momentum of the two particle system, when taken about point P, is not conserved.

## Homework Equations

L = r X p

theta = 90 degrees

## The Attempt at a Solution

So what I've done is find angular momentum for either mass, separately.

Doing the following:

L_1 = R x P

= |r||p| sin(theta)

= (a^2+d^2)^(1/2)* ma(omega)

L_2 = R x P

= |r||p| sin(theta)

= (a^2+d^2)^(1/2)*2ma(omega)

What I want to do... by intuition... is just add these two together. but they're magnitudes not vectors... so i am a bit confused if I can.

If not, what the heck do I do?

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