Angular momentum

1. Apr 22, 2005

tony873004

An aircraft of mass 10,000 kg is 100 km northwest of Pittsburgh at an altitude of 3000 m flying due east at 300 km/h. What is its angular momentum about Pittsburgh?

L=rp sin theta

for r, would I use 100 km (converted to m)
Or the closest approach to pittsburgh, which would be cos(45*300km/h)

For velocity in computing p, would I use 300 km/h (converted to m/s) or only its radial component to pittsburgh which is 300 / sin 45

2. Apr 22, 2005

OlderDan

There are lots of ways to approach this. You just have to be consistent. r*sin theta should be the same wherever you calculate it. The radial component of p would not contribute to the angular momentum

Last edited: Apr 22, 2005