Angular momentum

devious_

A uniform solid cylindrical drum of mass 1.5kg and radius 0.5m is free to rotate about a fixed, smooth, horizontal axis which coincides with the axis of the cylinder. The axis is at a height of 2m above a horizontal table, and a light string of AB of length 4m has one end attached to the heighest point of the cylinder. A block of mass 0.3kg is attached to end B of the string and rests on the table. The drum begins to rotate at a constant angular speed of 4 rad s-1 in a clockwise direction. Calculate the angular speed of the drum immediately after the block is jerked into motion.

I have no idea how to approach this question! The answer is supposed to be 2.86 rad s-1.

Any help is greatly appreciated. Attachments

• 608 bytes Views: 273
Last edited:
Related Introductory Physics Homework Help News on Phys.org

whozum

I'm looking at this and the only thing i can think of is to find the angular acceleration of the drum due to the block pulling it down.

devious_

I think the way I'm supposed to approach this question is by equating the sums of initial and final angular momentum for both the drum and the block. I can do the drum just fine, but all my attemps of finding the angular momentum of the block didn't produce the required answer.

Here's what I get for the drum:
initial angular momentum = moment of inertia * angular speed = 3/16 * 4 = 0.75 Nms
final angular momentum = 3/16 w, where w is the new angular speed

whozum

Ohhh right. Ofcourse.

The final moment of inertia has changed, because its now pulling the block. You can simplify the block as a point mass at point A, and find the new MOI.

devious_

I tried that:
final angular momentum = [3/16 + 0.3*(2^2 + 0.5^2)] w = 1.4625w
conservation of angular momentum => w = 0.75/1.4625 = 20/39

Which isn't the right answer. Am I doing something wrong?

whozum

final angular momentum = [3/16 + 0.3*(2^2 + 0.5^2)] w = 1.4625w

Your radius isnt right. How far is the point A from the axis of rotation?

devious_

If I take it to be at point A then I get the right answer! But.. Why should it be at point A?

devious_

I thought about it a bit and this is what I concluded:
Initial jerk turns the drum 4 rad, and so the block is pulled up 4*0.5 m, because A turns an arc length $r \theta$. So the block adheres to the circumference of the circle and can be considered as a point mass 0.5m away from the axis of rotation.

Is this correct?

whozum

Exactly, the block is 'pulling' or resisting motion AT the radius 0.5m, thus you can treat it as a particle in motion at the edge of the drum. Good thinking.

devious_

Thanks for the help -- and good night!

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving