Three equal mass, m are conected to vertices of an equilateral triangle, with edges of length L. Edges are massless.The triangle rotates with constant angular velocity Ï‰ about an axis through its center of mass, perpendicular to the triangle plane. At t=0 mass 1 is released, at a very short period from the triangle. To answer use m l Ï‰. Calculate the angular velocity of the two masses that stay connected. To answer this I need to find the angular momentum at point A (center of mass of the two masses) but why before they released the angular momentume is LA=LCM+rxmvcm isn't angular momentum suppose to be calculated about the same point in this ces A? and according to this equation angular momentum is also calculated about the center of mass, is that wrong? Thank you in advance!