A problem has arisen in teh goods yard where a large container is required to be pulled along a makeshift alipway. The container has a mass of 1.5tonne and is pulled along the horizontal slipway at an acceleration of 0.9m/s² by a rope wound around a winding drum. The resistance to motion of the container is equivalent to a coefficient of friction 0.6. The winidng drum hasa mass of 0.5 tonne, outside diameter 1m and radius of gyration of 0.3m. The drum has a resistance couple of 200Nm acting on it. Find teh torque required by the motor of teh winidng drum?

I have so far:

Q(Anglaur acceleration, cant get right sybol)

I=mk²

500x0.3² =45kgm²

Q=a/r

Q=0.9/0.5

=1.8 rad/s²

f=ma

p-f=ma

p=ma + f

(1500x0.9) + 0.6

=1350.6N

∑T=IK

E-Pr-R=IK

E=IQ+Pr+R

(45x1.8)+(1350x0.6x0.5) +200

=956.3Nm

That correct?

Cheers