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**A mass of 5g is required to balance a motorcar wheel. If the mass is attached to the 0.33m diameter wheel rim, calculate the centrifugal force acting on the rim of the wheel. The speed of rotation is 521 rev/min.**

**ω= 2∏N/60**

F= M ω

F= M ω

^{2}T**ω=2∏*521/60 = 54.6 rad/s**

F= 5*10

F= 5*10

^{-3}*(54.6)^{2}*TI am not sure how to find T and wonder if anyone can help?