1. The problem statement, all variables and given/known data A particle of mass 0.500 kg is attached to the 100 cm mark of a meter stick of mass 0.175 kg. The meter stick rotates on a horizontal, frictionless table with an angular speed of 5.00 rad/s. (a) Calculate the angular momentum of the system when the stick is pivoted about an axis perpendicular to the table through the 30.0 cm mark. (b) What is the angular momentum when the stick is pivoted about an axis perpendicular to the table through the 0 cm mark? 2. Relevant equations 1/12(mD^2) + mD^2 3. The attempt at a solution I am close to the correct answer, but only within 10%. I know it has to do with the fact the mass is not in the center of mass. So in the second part of the equation stated above I have substituded D=.7D^2. Any ideas? I am having trouble with the concept on this problem too.