Homework Help: Angular motion

1. Jan 6, 2005

mattmets

A coin with a diameter of 2.30 cm is dropped onto a horizontal surface. The coin starts out with an initial angular speed of 18.4 rad/s and rolls in a straight line without slipping. If the rotation slows with an angular acceleration of magnitude 2.17 rad/s2, how far does the coin roll before coming to rest?

Can anyone help- I'm trying to study for a physics final and I'm getting nowhere!!! Thanks.

2. Jan 6, 2005

Chen

Unless I'm missing something here, you can use this formula:

vf2 = vi2 + 2aΔx

Dividing both sides by R2, the coin's radius squared, we get:

ωf2 = ωi2 + 2αΔθ

Where α is the coin's angular acceleration, which is negative in this case. From here you can find Δθ and multiplying by R you can find the total distance travelled by the coin.

Last edited: Jan 6, 2005
3. Jan 6, 2005

mattmets

Great.....thanks