On a frictionless table, a glob of clay of mass 0.740 kg strikes a bar of mass 1.740 kg perpendicularly at a point 0.140 m from the center of the bar and sticks to it. If the bar is 0.660 m long and the clay is moving at 9.600 m/s before the impact, what is the final speed of the center of mass?(adsbygoogle = window.adsbygoogle || []).push({});

I have solved this part. The next part is the one I'm stuck on.

At what angular speed does the bar/clay system rotate about its center of mass after the impact in radians/second?

I have tried conservation of energy 1/2m1v1 = 1/2m2v2 + 1/2 Iw^2 but my answer is wrong.

Final equation. w = (m1v1-m2v2)/(1/2ML^2)

Could someone tell me where I went wrong?

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# Homework Help: Angular speed around a bar/clay system's center of mass after impact

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