1. Relevant information A bob of mass 0.5kg is attached to one end of a light inextensible string of length 0.500 m, whose other end is attached to a fixed pivot. The bob performs uniform circular motion in a horizontal plane, with the string making an angle of 30.0° with the vertical. 2. Question What is the angular speed of this circular motion? Hint: you can begin by using Newton's second law in the vertical direction to find the tension in the string.) 3. The attempt at a solution Tension in string F Cos 30 = 0.5 x 9.81 F = (0.5 x 9.81) / Cos 30 F = 5.66N Radius of circle must be 0.5x Sin 30 = 0.25m F = mass x radius x angular speed^2 Angular speed = Sqrt ( 5.66 / (0.5 x 0.25)) Angular speed = 6.72 rad s^-1 Have I done this right?