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Homework Help: Angular Speed of a Pulsar

  1. Mar 10, 2005 #1
    A pulsar is a rapidly rotating neutron star that continuously emits a beam of radio waves in a searchlight manner. Each time the pulsar makes one revolution, the rotating beam sweeps across the earth, and the earth receives a pulse of radio waves. For one particular pulsar, the time between two successive pulses is 0.0336 s. Determine the average angular speed (in rad/s) of this pulsar.

    i got w= change in theta / change in time
    6369/.0336
     
  2. jcsd
  3. Mar 10, 2005 #2

    dextercioby

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    What's 6369...?

    Daniel.
     
  4. Mar 11, 2005 #3
    Are you at RIT? Physics 312?
     
  5. Mar 11, 2005 #4
    Oh, wow! I'm at RIT in Physics 312. Are we classmates?
     
  6. Mar 11, 2005 #5
    no... OU phys 201
     
  7. Mar 12, 2005 #6
    The rotation between 2 pulses is 1 revolution = [itex]2\pi[/itex] and the time it takes to make one revolution is [itex]\Delta T=0.0336s[/itex]

    [tex]\omega=\frac{\Delta \Theta}{\Delta T}=\frac{2\pi}{0.0336 s}[/tex]

    Not sure where you got 6369 from, but the above should give you the right answer.
     
    Last edited: Mar 12, 2005
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