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**1. Homework Statement**

A playground merry-go round of Radius R=2.00m has a moment of

inertia I = 250 kg.m^2 and is rotating at 10.0 rev/min about a frictionless

vertical axle. Facing the axle a 25.0kg child hops onto the merry go round

and manages to sit down on the edge. What is the new angular speed of

the merry go round?

**2. Homework Equations**

I = 250 kg.m^2

10.0 rev/min

25.0kg child

radius = 2.00m

I=r^2m

L = r x p

L = Iw

**3. The Attempt at a Solution**

I = r^2m

m = I/r^2

m = 250kg.m^2/(2.00m)^2 = 62.5kg

I added the 62.5kg + 25.0kg = 87.5kg

I = r^2m

= (2.00m)^2(87.5kg) = 350kg.m^2

I don't know what to do with this from here.

Thanks for any help,

Kevin

**1. Homework Statement**

**2. Homework Equations**

**3. The Attempt at a Solution**