(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A playground merry-go round of Radius R=2.00m has a moment of

inertia I = 250 kg.m^2 and is rotating at 10.0 rev/min about a frictionless

vertical axle. Facing the axle a 25.0kg child hops onto the merry go round

and manages to sit down on the edge. What is the new angular speed of

the merry go round?

2. Relevant equations

I = 250 kg.m^2

10.0 rev/min

25.0kg child

radius = 2.00m

I=r^2m

L = r x p

L = Iw

3. The attempt at a solution

I = r^2m

m = I/r^2

m = 250kg.m^2/(2.00m)^2 = 62.5kg

I added the 62.5kg + 25.0kg = 87.5kg

I = r^2m

= (2.00m)^2(87.5kg) = 350kg.m^2

I don't know what to do with this from here.

Thanks for any help,

Kevin

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Angular Speed

**Physics Forums | Science Articles, Homework Help, Discussion**