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A gymnast is performing a forward double somersault.

The gymnast’s initial angular velocity is 0 rad/s.

The gymnast generates a 115 N-m torque.

The torque is applied to the gymnast’s body for 0.22 s.

In the layout position, the gymnast’s moment of inertia is 11.4 kg-m2

What is her angular acceleration and her final angular velocity (during layout position)?

Heres what i got

Angular acceleration

T=Iα

115 Nm=11.4 kg-m2(α)

115 Nm/11.4 kg-m2 = 11.4 kg-m2(α)/ 11.4 kg-m2 =10.08 kg-m2

Angular velocity (w)

Tt=I(w)

104 Nm (.22s) = 11.4kg-m2(w)

104Nm(.22s) / 11.4kg-m2 = 11.4kg-m2(w) / 11.4kg-m2 = 2.22 kg-m2

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# Homework Help: Angular velocity and acceleration

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