Angular velocity of an arrow

  • Thread starter Dansuer
  • Start date
  • #1
Dansuer
81
1

Homework Statement


A wheel has six spokes of length 30 cm. The wheel is rotating with an angular velocity of 2.5 rotation per second. We want to throw an arrow, of length 24 cm, through the wheel. What is the minimal velocity required for the arrow to go through the wheel without touching the spokes.


Homework Equations



v = s / t

[tex]\omega[/tex] = [tex]\theta [/tex] / t

The Attempt at a Solution



The times for the arrow to go through have to be equal the time one spoke goes around 1/6 of the wheel.

so the system: v = s/t and [tex]\omega[/tex] = [tex]\theta [/tex] / t

gives: v = ([tex]\omega[/tex] / [tex]\theta [/tex]) * s

[tex]\omega[/tex] = 2.5 rotation per second * 360degree = 900 degree/s

[tex]\theta [/tex] = 360 degree / 6 = 60 degree

v = ([tex]\omega[/tex] / [tex]\theta [/tex]) * s = (900 degree/s / 60 degree) * 24 cm = 360 cm




is this right?
 

Answers and Replies

  • #2
cupid.callin
1,137
0
first, speed is not in cm.

second, convert 24 cm into m

rest is perfectly correct
 
  • #3
tiny-tim
Science Advisor
Homework Helper
25,838
255
Hi Dansuer! :smile:

(have a theta: θ and an omega: ω :wink:)

Yes, that looks fine, except for the units …

your speed should be 360 cm/s, not 360 cm, shouldn't it? :wink:

(since the question is entirely in cm, I suspect it may not be necessary to convert to m/s)

However, since the arrow is shorter than the radius, you can just throw the arrow gently sideways! :rofl:​
 
  • #4
Dansuer
81
1
thanks a lot for your answers !
 

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