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**At time t= 0 a grinding wheel has an angular velocity of 22.0 rad/s . It has a constant angular acceleration of 26.0 rad/s^2 until a circuit breaker trips at time t= 2.30 s . From then on, the wheel turns through an angle of 436 rad as it coasts to a stop at constant angular deceleration.**

a. Through what total angle did the wheel turn between and the time it stopped?

Express your answer in radians.

a. Through what total angle did the wheel turn between and the time it stopped?

Express your answer in radians.

[tex]\Delta \Theta = 13t^2 + 22t [/tex] at t=2.3s is 119.4rad

Therefore total angle is 119 + 436 = 555rad

**b. At what time does the wheel stop?**

Express your answer in seconds.

Express your answer in seconds.

So I know that [tex] \omega_{f} = 0 [/tex] for the wheel to stop

[tex] \omega_{i} = 22.0 rad/s [/tex]

That's as much as I understand...

**c. What was the wheel's angular acceleration as it slowed down?**

Express your answer in radians per second per second.

Express your answer in radians per second per second.

Would I use this equation [tex] \omega_{f} = \omega_{i} + \alpha t [/tex]

and just solve for [tex]\alpha[/tex]?

[tex] \omega_{f} = 0

\omega_{i} = 22.0

t = time solved in part b [\tex]