A solid uniform disk of mass m and radius R is pivoted about a horizontal axis through its center, and a small body of mass m is attached to the rim of the disk. If the disk is released from rest with the small body at the end of a horizontal radius, find the angular velocity when the body is at the bottom. Loss of P.E., = gain in K.E. Therefore m*g*R = .5*I*w^2 + .5*m*v^2. Where I = rotational inertia and w = angular velocity. w=2*(g*R - 2*v)/R^2)^2. Is this correct, if it isn't why or where? Thanks very much.