# Angular Velocity/Spinning Disk

1. Jun 16, 2012

### SalsaOnMyTaco

1. The problem statement, all variables and given/known data
Ive been working on this two last questions and I cant seem to get the right set up.

A disk with a diameter of 0.04 m is spinning with a constant velocity about an axle perpendicular to the disk and running through its center.

-How many revolutions per second would it have to rotate in order that the acceleration of the outer edge of the disk be 14 g's (i.e., 14 times the gravitational acceleration g)?
13.19 rev/s

For the frequency determined in part (a), what is the speed of a point half way between the axis of rotation and the edge of the disk?
.828 m/s

At this same frequency, what is the period of rotation of this "halfway point"?

How long does it take a point on the edge of the disk to travel 1 km?

2. Relevant equations
Period (time)
T= 2∏/ω

Centripetal Acceleration
α=rω2

3. The attempt at a solution

First, I try to find the angular velocity at the halfwaypoint

then i punch in

Once i typed in the answer, it says is wrong

2. Jun 16, 2012

### SalsaOnMyTaco

woah okay no, should i find the frequency and then divide 1/f ?

3. Jun 16, 2012

### tiny-tim

Hi SalsaOnMyTaco!
Why would the angular velocity be any different?

4. Jun 16, 2012

### TSny

Why did you use .01 m for r? Note that it's 14 g's at the outer edge.

Last edited: Jun 16, 2012
5. Jun 16, 2012

### SalsaOnMyTaco

isnt velocity different on a different part of the radius

The total diameter of the disk is .04, radius is .02, half way of the radius is .01

6. Jun 17, 2012

### TSny

But the problem states that the acceleration is 14 g's for a point on the outer edge of the disk (r = 0.02 m), not at a halfway point (r = 0.01 m).

7. Jun 17, 2012

### tiny-tim

ahh!

you're confusing angular velocity with tangential velocity (ie component of velocity along the "angular" unit vector $\boldsymbol{\hat{\theta}}$)

angular velocity is angle per second, dθ/dt, it's not a velocity at all