The question: A wheel was rotating at 12.5 rad/s when a torque was applied for 15.7 s. The angular velocity increased to 54.0 rad/s. What angle did the wheel turn through in that time? My Solution: theta = Wo*t+1/2*a*t^2 = (12.5 rad/s)(15.7)+(1/2)(41.5)(15.7)^2 therefore, theta = 5310.9 rad. Comment: This answer doesn't seem right to me and I am stuck on what to do. Thank you in advance!