When a proton is annhilated, is there gamma radiation emitted?
Why not crunch the numbers and see - what frequency radiation results? Is that part of the EM spectrum corresponding to "gamma radiation"?
I already crunched numbers got .6 picometer wavelength, so i am just checking .....
OK - so does that correspond to the gamma-ray wavelength?
Did you look it up to see?
What do you mean by this? A proton is not going to simply disappear. You need to specify the process you have in mind. Once you have done that, you can start looking at reaction rates and different channels and cross sections.
In addition to Orodruin's answer: the process you might have in mind is extremely unlikely.
Annihilation does not always produce photons, and "two photons and nothing else" is a very special case.
I know, you guys are assuming i am trying to solve some problem the situation is that a photon is annhilated in the presence of a stationary electron, forming an electron positron pair along with the original electron. Y+e=e+e+e
What is the average number of pions produced by proton annihilation? 4,5?
Maximum is 13 (from pion rest mass). Minimum... 1 is obviously impossible (conservation of momentum), but is 2 pions a legal option, and if so then how frequent?
... that is different from the description in post #1 and the title where you said a proton was being annihilated.
The process: ##\gamma + e \rightarrow e+(e+\bar e)## ... is called "pair production", not "annihilation".
5 (experiment, theory). There was some better experimental paper I don't find any more.
@SU403RUNFAST: The additional emission of a photon in the process Simon Bridge described is possible, but the emitted photon there does not have a fixed energy then.
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