# Annihilation Operator Hermitian?

## Homework Statement

How do I show that the annihilation operator $$\hat{a}$$ is hermitian WITHOUT explicitly using the condition where an operator X is hermitian if its adjoint is also X ie. $$X=X^+$$

none.

## The Attempt at a Solution

I could show $$\hat{a} \hat{x} \neq \hat{x} \hat{a}$$ where $$\hat{x}$$ is the position operator, but that only shows non-hermiticity for that one operator...
Is there a more elegant way to show non-hermiticity simply?

Dick
Homework Helper
Commuting with operators doesn't have much to do with hermiticity. In the last problem you posted you found an eigenstate of the 'a' operator. What were it's eigenvalues like? Hermitian operators have real eigenvalues.

oh yes offcourse - the eigenvalue was real...stupid me.

Dick