- #1
Shadowz
- 43
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So we all know about [tex]a[/tex] and [tex]a^\dagger[/tex].
My problem says that if [tex]f(a^\dagger)[/tex] is an arbitrary polynomial in [tex]a^\dagger[/tex] then [tex]af(a^\dagger)|n> = \frac{df(a^\dagger)}{da}|0>[/tex] where |0> is the ground state energy. How can I go about proving this?
A hint would be highly appreciated.
Thanks,
My problem says that if [tex]f(a^\dagger)[/tex] is an arbitrary polynomial in [tex]a^\dagger[/tex] then [tex]af(a^\dagger)|n> = \frac{df(a^\dagger)}{da}|0>[/tex] where |0> is the ground state energy. How can I go about proving this?
A hint would be highly appreciated.
Thanks,