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A mass of 1.64 kg stretches a vertical spring 0.300 m. If the spring is stretched an additional 0.123 m and released, how long does it take to reach the (new) equilibrium position again?

What I tried:

Found k using F=kx (mg=kx)

using that k, I calculated the force in the extended spring (F=k(0.123))

using that force, I calculated the acceleration of the mass (F=ma)

finally, using x=(1/2)at^2 I calculated t.

I must be missing something obvious b/c this doesnt seem like a difficult problem...

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# Homework Help: Annoying Spring Problem

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