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Homework Help: Another Angular Momentum

  1. Dec 2, 2004 #1
    A light, rigid rod 1 meter in length roatets about an axis perpendicular to its length and its center. Two particles of masses 4 KG and 3 KG are connected to the ends of the rod. What is the angular momentum of the system if the speeds of earch particle is 5 m /s

    Curious if this is right

    L=Iw
    Both are point masses so I=MR^2, so I
    =(4KG)(.5M^2) + (3KG)(.5^2)

    w=r/v
    w=.5/5 = 1/10

    So plug this all back into L=IW

    [(4KG)(.5M^2)+(3KG)(.5M^2)]x.1
     
  2. jcsd
  3. Dec 2, 2004 #2

    BobG

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    Science Advisor
    Homework Helper

    One slight change.

    [tex]v=r\omega[/tex]

    so:

    [tex]\frac{v}{r}=\omega[/tex]
     
  4. Dec 2, 2004 #3
    Ah so its 5/.5 so 10, thanks!
     
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