# Another calc. question to check!

1. Jun 8, 2005

### laker_gurl3

Find the area bounded by y=sin(x) and y= x(pi)/12

the final answer i got was A= 1.969

2. Jun 8, 2005

### OlderDan

If that second function is y = x*pi/12 it is not correct

3. Jun 8, 2005

### laker_gurl3

yeah..that's the second function..
well im checking it over again, im not sure how else i can do it

4. Jun 9, 2005

### laker_gurl3

just to make sure, another way to write the second function is , (X/12) multiplied by pi

5. Jun 9, 2005

### OlderDan

That is correct. And you are trying to find the area bounded by the two functions. What integral are you doing, including the limits you are using?

6. Jun 9, 2005

### laker_gurl3

i am using 2.446 and 0

2.446 2.446
| |
| sin (x) - | (x/12) multipled by pi
| |
0 0

7. Jun 9, 2005

### OlderDan

Those are the correct limits. The correct answer is less than 1. Are you using a calculator function to integrate, or doing it by hand?

8. Jun 9, 2005

### laker_gurl3

Well, the first part of the answer i got was .9845.. Then i multiplied by 2 to get the area of the other side... does that sound good?

9. Jun 9, 2005

### OlderDan

OK sorry. I assumed you were talking about one side. My mistake.

You should have said your limts were from -2.446 to +2.446 with positive areas

Last edited: Jun 9, 2005