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Another calc. question to check!

  1. Jun 8, 2005 #1
    Find the area bounded by y=sin(x) and y= x(pi)/12

    the final answer i got was A= 1.969

    Can anyone please confirm this?
     
  2. jcsd
  3. Jun 8, 2005 #2

    OlderDan

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    If that second function is y = x*pi/12 it is not correct
     
  4. Jun 8, 2005 #3
    yeah..that's the second function..
    well im checking it over again, im not sure how else i can do it
     
  5. Jun 9, 2005 #4
    just to make sure, another way to write the second function is , (X/12) multiplied by pi
     
  6. Jun 9, 2005 #5

    OlderDan

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    That is correct. And you are trying to find the area bounded by the two functions. What integral are you doing, including the limits you are using?
     
  7. Jun 9, 2005 #6
    i am using 2.446 and 0

    2.446 2.446
    | |
    | sin (x) - | (x/12) multipled by pi
    | |
    0 0
     
  8. Jun 9, 2005 #7

    OlderDan

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    Those are the correct limits. The correct answer is less than 1. Are you using a calculator function to integrate, or doing it by hand?
     
  9. Jun 9, 2005 #8
    Well, the first part of the answer i got was .9845.. Then i multiplied by 2 to get the area of the other side... does that sound good?
     
  10. Jun 9, 2005 #9

    OlderDan

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    OK sorry. I assumed you were talking about one side. My mistake.

    You should have said your limts were from -2.446 to +2.446 with positive areas
     
    Last edited: Jun 9, 2005
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