- #1
kdinser
- 337
- 2
it's a diff eq problem
dN/ds=k(250-s)
The way I'm doing it. (S=integral sign)
SdN/ds=k[S250 ds - Ss ds]
N = k[250s-(s^2)/2]+C
Not sure where I'm going wrong here, but it looks nothing like the answer in the solution manual which just jumps from Sk(250-s)ds to -k/2(250-s^2)^2+C
Thanks for any help.
dN/ds=k(250-s)
The way I'm doing it. (S=integral sign)
SdN/ds=k[S250 ds - Ss ds]
N = k[250s-(s^2)/2]+C
Not sure where I'm going wrong here, but it looks nothing like the answer in the solution manual which just jumps from Sk(250-s)ds to -k/2(250-s^2)^2+C
Thanks for any help.