- #1

- 52

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**[SOLVED] another chain rule: easy one**

[tex]y=xe^{-x^2}[/tex]

i have no i dea how to start.

[tex] f'= x^{x^2} or -2x^blah blah blah [/tex]

just get me started and i'll promise you i will finish it myself

Last edited:

- Thread starter physicsed
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- #1

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- 0

[tex]y=xe^{-x^2}[/tex]

i have no i dea how to start.

[tex] f'= x^{x^2} or -2x^blah blah blah [/tex]

just get me started and i'll promise you i will finish it myself

Last edited:

- #2

- 1,341

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This is actually an application of the product rule, then the chain rule.

- #3

- 49

- 1

You will probably want to use the product rule and the rule for finding the derivative of [tex]e^{g(x)}[/tex][tex]y=xe^{-x^2}[/tex]

i have no i dea how to start.

[tex] f'= x^{x^2} or -2x^blah blah blah [/tex]

just get me started and i'll promise you i will finish it myself

- #4

- 1,752

- 1

[tex]f(x)=e^{-x^2}[/tex]

derivative of e is itself, times the derivative of it's exponent.

- #5

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wow 3 replies all at 22:49 ... you just got the royal treatment :D

- #6

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ROFL:rofl:wow 3 replies all at 22:49 ... you just got the royal treatment :D

- #7

Dick

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- #8

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Solved it

thanks

thanks

- #9

Dick

Science Advisor

Homework Helper

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Geez. I'm really late.

- #10

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[tex] Y'= e^{-x2}(1-2x^{2})[/tex]

thanks for the help

thanks for the help

- #11

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Looks right^^

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