At two different points of an irregularly shaped conductor, the field had the following two values(adsbygoogle = window.adsbygoogle || []).push({});

5.6*10^4 and 2.8*10^4 respectively. Find the local surface charge density at;

1- the point with the greatest radius of curvature,

2- the point with the smallest raduis of curvature.

I know that at the point with the smallest radius of curvature, charges tend to accumulate, meaning that the first field corresponds to the point of the smallest radius of curvatire and I used E = sigma/epsilon_naught to find the two local charge densities. The answers I have is the reverse of what I got, He gave he one I had for the smallest r as the one of the greatest r! Is there anything wrong here, me or him?

M B

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# Homework Help: Another charge density

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