- #1
fredrick08
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Homework Statement
f(z)=u(r,theta)+iy(r,theta)... where x=rcos(theta) and y=rsin(theta), use chain rule to show that [tex]\partial[/tex]u/[tex]\partial[/tex]r=1/r([tex]\partial[/tex]v/[tex]\partial[/tex][tex]\theta[/tex]) and [tex]\partial[/tex]v/[tex]\partial[/tex]r=-1/r([tex]\partial[/tex]u/[tex]\partial[/tex][tex]\theta[/tex]) are equivelent to the cauchy riemann equations.
Homework Equations
CR equations: [tex]\partial[/tex]u/[tex]\partial[/tex]x=[tex]\partial[/tex]v/[tex]\partial[/tex]y and [tex]\partial[/tex]u/[tex]\partial[/tex]y=-[tex]\partial[/tex]v/[tex]\partial[/tex]x
The Attempt at a Solution
Ok the I am unsure by how i am meant to use the chain rule here? and instead of typing out the dirvative I am goin to just write i.e d/dx..
i did, dz/dr=dz/dx*dx/dr=1(cos(theta) and dz/dtheta=dz/dy*dy/dtheta=rcos(theta)... but that doesn't make sense... its the same as the provided equations without the 1/r.. but if i do the CR equations i get, du/dx=1 and du/dy=0?