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Another Derivate

  1. Jun 12, 2004 #1
    Thanks for your help....

    How about this one?

    Using the definition of derivate find f ` (x)

    f(x) = x/(2x-1)

    f ` (x) = lim h->0 [(f(x+h)) – (f(x))]/h

    lim h->0 ([((x+h) / (2x+2h-1))-(x/(2x-1))]/h) . [((2x+2h-1)(2x-1)) / ((2x+2h-1)(2x-1))]

    lim h->0 [(2x^2)-x+(2xh)-h-(2x^2)-(2hx)+x]/(h(2x+2h-1)(2x-1))

    lim h->0 -h/(h(2x+2h-1)(2x-1)) = -1/(2x-1)^2
     
    Last edited: Jun 12, 2004
  2. jcsd
  3. Jun 12, 2004 #2

    arildno

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    If f(x)=x/(2x-1), then it is correct.
     
  4. Jun 12, 2004 #3
    typo

    yes...thanks
     
  5. Jun 12, 2004 #4

    arildno

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    just a suggestion, ladyrae:
    if you have more questions on this, don't open any new thread, continue to use this instead.
    In addition, try to learn LATEX formatting, it's not very difficult..
     
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