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Another Electric Field Problem

  1. Mar 1, 2012 #1
    1. The problem statement, all variables and given/known data
    Two charges, one at the origin and one at x=1.6 m produce a field 1.59x10^3N/C at x = 9.11 m. The charge at the origin has a charge of 1.11 x 10^-5 C. How much charge does the second charge have?

    http://books.google.com/books?id=vN...the origin has a magnitude of 845 N/C&f=false

    Page 96 Question 3.49

    2. Relevant equations

    E=F/q
    E=kq1q2/r^2
    k=8.99x10^9


    3. The attempt at a solution

    I tried using coulomb's law to find Q2

    1590=(9x10^9)(1.11x10^-5)(q2)/(9.11^2)

    But my solution did not match the answer which was q2 = 2.44x10^-6C
     
  2. jcsd
  3. Mar 2, 2012 #2

    vela

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    That's not the correct equation for the electric field due to a point charge. You have the equation for the force between two point charges. It's not really useful for this problem.
     
  4. Mar 11, 2012 #3
    ah yes i got it ty
     
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