- #1
murshid_islam
- 457
- 19
how to find the integer solutions of the following equation:
[tex]x^3 + x^{2}y + xy^2 + y^3 = 8(x^2 + xy + y^2 + 1)[/tex]
after simplifying, i got,
[tex](x^2 + y^2)(x + y - 8) = 8(xy + 1)[/tex]
from this, i can see that x and y are both odd or both even. but what should i do next. i tried putting x = 2p and y = 2q but that's not going anywhere.
thanks in advance.
[tex]x^3 + x^{2}y + xy^2 + y^3 = 8(x^2 + xy + y^2 + 1)[/tex]
after simplifying, i got,
[tex](x^2 + y^2)(x + y - 8) = 8(xy + 1)[/tex]
from this, i can see that x and y are both odd or both even. but what should i do next. i tried putting x = 2p and y = 2q but that's not going anywhere.
thanks in advance.