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Hi. If using:
f (focal length) = a / ( 2 x arctan (theta / 2)) where a = 13 and is the Field of View
the value I get for the focal length is 0.03 and this seems too small. Unless the calculation has not been done right?
Thanks.
f (focal length) = a / ( 2 x arctan (theta / 2)) where a = 13 and is the Field of View
the value I get for the focal length is 0.03 and this seems too small. Unless the calculation has not been done right?
Thanks.