# Homework Help: Another force problem!

1. Sep 12, 2004

### pinky2468

Here is the question: A duck has a mass of 2.5kg. As the duck paddles, a force of 0.10N acts on it in a direction due east. In addition, the current of the water exerts a force of 0.20N in a direction of 52degrees south of east. When the forces begin to act, the velocity of the duck is 0.11m/s in a direction due east. Find the magnitude and direction (relative to due east) of the displacement that the duck undergoes in 3.0s while the forces are acting.
SO, I attemted to find the acceleration for the x and y and then use the tangent-1 to find the angle and the x=Vot + 1/2a(t)squared. Again not getting the answer in the back of the book 0.78m, 21degrees south of east
Obviously I am approaching this problem wrong?! Any advice??

2. Sep 12, 2004

### Staff: Mentor

Find the x and y components of the acceleration. Then use kinematic formulas to find the x and y components of the displacement. That sounds like what you are saying you did. Show your work so we can check it out.

3. Sep 12, 2004

### pinky2468

Rx=.20N(cos 52) + .10(cos 0)=.2231N Ry= .20(sin 52) + .10(sin 0)=.1576N

Ax=.2231N/2.5kg= .08924 Ay=.1576N/2.5kg= .0252

What step am I missing or am I completely off track?

4. Sep 12, 2004

### Staff: Mentor

You are not off track, you are just making mistakes.
OK.

OK.
Not OK. Do over.

5. Sep 12, 2004

### Pyrrhus

Pinky did you see that the initial velocity has only a non-zero component which is its horizontal?

6. Sep 12, 2004

### Staff: Mentor

I spoke too soon before. You are a bit off track. In addition to your mistake that I already pointed out:
It looks like you are finding the angle of the force. But you should be finding the angle of the displacement, not the force.
That's just the x-component! Don't forget to find the y-component, and then the total displacement.

7. Sep 12, 2004

### pinky2468

OK! I finally got it! Thanks!