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[itex]\int \frac{\cot x}{\sin x}\,dx[/itex]

If anyone can aid me in solving this I would be very glad. Thanks in advance.

- Thread starter Ornum
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- #1

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[itex]\int \frac{\cot x}{\sin x}\,dx[/itex]

If anyone can aid me in solving this I would be very glad. Thanks in advance.

- #2

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[tex]

{d \over {dx}}({1 \over {f(x)}}) = {{ - f'(x)} \over {f(x)^2 }}

[/tex]

- #3

AKG

Science Advisor

Homework Helper

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In many situations, it's really simple just to express everything in terms of sine and cosine:Ornum said:

[itex]\int \frac{\cot x}{\sin x}\,dx[/itex]

If anyone can aid me in solving this I would be very glad. Thanks in advance.

[itex]\int \frac{\cos x}{\sin ^2 x}\,dx[/itex]

Let [itex]u = \sin x[/itex], therefore [itex]dx = du/\cos x[/itex]. Making the substitution:

[itex]\int \frac{du}{u^2} = -u^{-1} + C = -\csc x + C[/itex]

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Paul.

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Paul.

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INTEGRAL OF cosx cosec(sqr)x

take cosec(sqr)x as 2nd function and integrate by parts ...gives u answer instantly...

- #8

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I = inverse trigonometric function

L = logarithmic function

A = algebraic function

T = trigonometric function

E = exponential function

This order gives you an idea of which function to chose as u and which to chose v, when you wish to evaluate the integral [tex]\int u dv[/tex].

[tex]

\int udv = uv - \int vdu

[/tex]

By the way, Dr. Brain are you from India? My guess is that you're in class 11/12. Correct me if I am wrong ;-)

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