- #1

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I'm uncertain how to find this integral, or even how to start it. Any guidence would be appreciated. Thanks.

Steve

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- Thread starter Stevecgz
- Start date

- #1

- 68

- 0

I'm uncertain how to find this integral, or even how to start it. Any guidence would be appreciated. Thanks.

Steve

- #2

James R

Science Advisor

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Hmm... integration by parts, perhaps?

Last edited:

- #3

TD

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[tex]\int {\left( {4 - 2x} \right)\sqrt {4x - x^2 } dx} [/tex].

If not, you'll need integration by parts indeed and I suspect you'll be getting an arcsin too

Think about

[tex]\sqrt {4x - x^2 } = \sqrt {4 - \left( {x - 2} \right)^2 } = 2\sqrt {1 - \left( {\frac{{x - 2}}

{2}} \right)^2 } [/tex]

- #4

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Thanks TD, got it worked out now.

Steve

Steve

- #5

TD

Homework Helper

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Good

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