1. Sep 25, 2005 #1

   Stevecgz

   

   [tex]\int (4-x)\sqrt{4x-x^2}dx[/tex]
   
   I'm uncertain how to find this integral, or even how to start it. Any guidence would be appreciated. Thanks.
   
   Steve

    

   Stevecgz, Sep 25, 2005
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3. Sep 25, 2005 #2

   James R

   

   Science Advisor

   Homework Helper

   Gold Member

   Hmm... integration by parts, perhaps?

    

   Last edited: Sep 25, 2005

   James R, Sep 25, 2005
4. Sep 26, 2005 #3

   TD

   

   Homework Helper

   It would be a lot easier if the integral were
   
   [tex]\int {\left( {4 - 2x} \right)\sqrt {4x - x^2 } dx} [/tex].
   
   If not, you'll need integration by parts indeed and I suspect you'll be getting an arcsin too
   
   Think about
   
   [tex]\sqrt {4x - x^2 } = \sqrt {4 - \left( {x - 2} \right)^2 } = 2\sqrt {1 - \left( {\frac{{x - 2}}
   {2}} \right)^2 } [/tex]

    

   TD, Sep 26, 2005
5. Sep 27, 2005 #4

   Stevecgz

   

   Thanks TD, got it worked out now.
   
   Steve

    

   Stevecgz, Sep 27, 2005
6. Sep 27, 2005 #5

   TD

   

   Homework Helper

   Good

    

   TD, Sep 27, 2005

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