# Homework Help: Another Kinematics 1-D

1. Jan 19, 2012

### saac

1. The problem statement, all variables and given/known data
Two people start from rest at 88m apart and walk directly toward each other. Person A has a magnitude of .3m/s^2, while person B has a magnitude of .2m/^2. Relative to person A's starting point, where do the people coincide?

2. Relevant equations
How to determine collision point?

3. The attempt at a solution
I've tried find the total time it takes for each to cover the 88m. then take those values and switch them between A & B. Otherwise i'm stuck.

2. Jan 19, 2012

### PhanthomJay

But each does not cover 88 m. They meet somewhere in between A and B, and arrive there at the same elapsed time.

3. Jan 19, 2012

### saac

So t1=t2 . Would velocity be calculated for A & B? and then find the displacement for each?

4. Jan 19, 2012

### PhanthomJay

It would be easier to write an equation to show how far A moves during t1, and how far B moves during time t1. Note that if A moves x meters during that time, then B moves 88-x meters during the time it takes them to meet.

5. Jan 19, 2012

### saac

ok makes sense. however, i do not understand how to utilize the accelerations? would the equation look like this: x/.3=88-x/.2?

6. Jan 20, 2012

### PhanthomJay

No, use the kinematic equation that relates distance as a function of acceleration and time.....