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Another Kinematics 1-D

  1. Jan 19, 2012 #1
    1. The problem statement, all variables and given/known data
    Two people start from rest at 88m apart and walk directly toward each other. Person A has a magnitude of .3m/s^2, while person B has a magnitude of .2m/^2. Relative to person A's starting point, where do the people coincide?


    2. Relevant equations
    How to determine collision point?


    3. The attempt at a solution
    I've tried find the total time it takes for each to cover the 88m. then take those values and switch them between A & B. Otherwise i'm stuck.
     
  2. jcsd
  3. Jan 19, 2012 #2

    PhanthomJay

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    But each does not cover 88 m. They meet somewhere in between A and B, and arrive there at the same elapsed time.
     
  4. Jan 19, 2012 #3
    So t1=t2 . Would velocity be calculated for A & B? and then find the displacement for each?
     
  5. Jan 19, 2012 #4

    PhanthomJay

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    It would be easier to write an equation to show how far A moves during t1, and how far B moves during time t1. Note that if A moves x meters during that time, then B moves 88-x meters during the time it takes them to meet.
     
  6. Jan 19, 2012 #5
    ok makes sense. however, i do not understand how to utilize the accelerations? would the equation look like this: x/.3=88-x/.2?
     
  7. Jan 20, 2012 #6

    PhanthomJay

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    No, use the kinematic equation that relates distance as a function of acceleration and time.....
     
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