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1. A stone is thrown vertically upward with a speed of 12.0 m/s from the edge of a cliff 70.0 m high (Fig. 2–34). (a) How much later does it reach the bottom of the cliff? (b) What is its speed just before hitting? (c) What total distance did it travel?

Okay. I understand everything conceptually. The stone is thrown up at a speed, and during that time it travels a certain distance above the cliff over a period of time before the stone reaches its highest point at which it's velocity is zero. Then, the rock falls the added distance and the 75 feet with earths acceleration of 9.8 meters/ s^2

I just don't know how to figure out what that added distance is. It is some 75+ x

help please