lim_x->0 (x + (1/x) ) sin(x)(adsbygoogle = window.adsbygoogle || []).push({});

As x goes towards 0, wouldn't 1/x go towards inf?

Thus

(x + (1/x)) should go towards inf as x goes towards 0?

sin(x) will go towards 0 as x goes towards 0, since sin(0) is 0.

Wouldn't that leave inf * 0 = undefined (or 0)?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Another limit problem.

**Physics Forums | Science Articles, Homework Help, Discussion**