(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

[tex] \lim_{u \to 1} \frac {(u-1)^{3}}{u^{-1}-u^{2}+3u-3} [/tex]

3. The attempt at a solution

So the first derivative is:

[tex] \lim_{u \to 1} \frac {3(u-1)^{2}}{-u^{-2}-2u+3} [/tex]

this limit also gives a 0/0 situation so take the derivative again:

[tex] \lim_{u \to 1} \frac{6(u-1)}{2u^{-3}-2} [/tex]

and this limit as well gives a 0/0 again, so would I do it again? or whats the next step? The book doesn't give me any instruction to this situation just to the 2nd derivative.

If I do take the derivative again it is -1, is that correct?

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# Homework Help: Another limit with l'hospital

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