- #1

Callumnc1

- 865

- 100

- Homework Statement:
- Please see below

- Relevant Equations:
- Please see below

For this problem,

The solution is

However could the bracket circled in red also be ## (x - \frac {L} {2})^{2} ## since the terms are squared? Also if anyone else knows a simpler way to solve this problem please let me know.

I though an easier way to solve this problem would be moving the origin such that it is in the middle of the rod then:

## dV = \frac {k_e dx} {x} ## Then integrate over rod from ## \frac {-L} {2} ## to ## \frac {L} {2} ## to get:

##V = k_e\log_eL ## since ##-In(-L)## is undefined. I guess the authors must of knew this and decided to have the origin at the left of the rod. Anybody else agree with that?

Many thanks!

The solution is

However could the bracket circled in red also be ## (x - \frac {L} {2})^{2} ## since the terms are squared? Also if anyone else knows a simpler way to solve this problem please let me know.

I though an easier way to solve this problem would be moving the origin such that it is in the middle of the rod then:

## dV = \frac {k_e dx} {x} ## Then integrate over rod from ## \frac {-L} {2} ## to ## \frac {L} {2} ## to get:

##V = k_e\log_eL ## since ##-In(-L)## is undefined. I guess the authors must of knew this and decided to have the origin at the left of the rod. Anybody else agree with that?

Many thanks!

Last edited: