Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Another necessary condition

  1. Oct 12, 2013 #1
    Starting from the Cauchy definition of convergence of a series :

    [tex]\forall N,\epsilon>0,\exists N_0 | k>N_0\Rightarrow |\underbrace{\sum_{n=1}^{N+k}u_n-\sum_{n=1}^k u_n}_A |<\epsilon[/tex]

    rewriting A in terms and considering a positive decreasing sequence :

    [tex]A\Rightarrow \epsilon>u_{N+k}+\ldots +u_{k+1}>Nu_{N+k}[/tex]

    one finds by taking the limit another necessary criterion :

    [tex]\lim_{n\to\infty}n u_n=0[/tex].

    This implies for example that the harmonic series cannot converge.

    My question is why we don't see this at school but only the condition [tex]u_n\to 0[/tex] ?
     
    Last edited: Oct 12, 2013
  2. jcsd
  3. Oct 12, 2013 #2
    You are imposing the additional restriction that you have a positive decreasing sequence. The "Divergence Test" that is taught in school applies to all series.
     
  4. Oct 13, 2013 #3
    Do you think it's possible to generalize this to any kind of series ?
     
  5. Oct 13, 2013 #4

    arildno

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    Dearly Missed

    Take the alternating harmonic series.
    It converges.
    But, it wouldn't, according to the simplest form of generalization of your criterion.
    The upshot is that it probably is VERY difficult to generalize this Cauchy criterion into an independent necessary criterion for convergence for series of a more general type than those with positive, decreasing terms.
     
    Last edited: Oct 13, 2013
  6. Oct 13, 2013 #5
    Right.
    I thought maybe it is possible to generalize to positive term series (not forcedly decreasing).

    The sum of the terms then becomes : [tex]Nu_m[/tex] where u_m is the minimum of the terms between N+k and k, but then remains to prove that m tends towards N when N tends to infinity, but I have no idea how to do that.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Another necessary condition
Loading...