An automobile cooling system holds 18 L of water. How much heat does it absorb if its temperature rises from 20oC to 90oC?(adsbygoogle = window.adsbygoogle || []).push({});

V= 18 L=0.018 m3

m=pV=(1.0*103 kg/ m3 )(0.018 m3 )= 18 kg

Q=mcT=(18 kg)(4186 J/kg*Co)( 90o-20o)= 5,274,360 J

The answer in the book says it should be 4.7*10^6, but I don't know how they derived to that answer. Any help

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# Homework Help: Another one

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