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  1. Nov 22, 2006 #1
    An automobile cooling system holds 18 L of water. How much heat does it absorb if its temperature rises from 20oC to 90oC?

    V= 18 L=0.018 m3
    m=pV=(1.0*103 kg/ m3 )(0.018 m3 )= 18 kg

    Q=mcT=(18 kg)(4186 J/kg*Co)( 90o-20o)= 5,274,360 J

    The answer in the book says it should be 4.7*10^6, but I don't know how they derived to that answer. Any help
  2. jcsd
  3. Nov 22, 2006 #2
    Any help from anybody?
  4. Nov 23, 2006 #3
    Are you sure that is all the information given? Your calculations seems right to me.
  5. Nov 23, 2006 #4
    Yes that was all that was given...I thought I was correct also, maybe the book made a mistake...it has been known to happen. Thanks for the help!
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