Basically I will have won if I can show that(adsbygoogle = window.adsbygoogle || []).push({});

[tex]n+1 \geq \left( 1+ \frac{1}{n} \right)^n[/tex]

can I? Not that I haven't tried...

This is also equivalent to showing that

[tex]n^n \geq (n+1)^{n-1}[/tex]

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# Another proof by induction

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