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**another "proof" that 2 = 1**

x

^{2}= x * x

x

^{2}= x * (1 + 1 + ... + 1) [assume there are "x" terms in the parentheses]

x

^{2}= (x + x + ... + x) [again, there are "x" terms in the parentheses]

now take derivatives of both sides:

2x = (1 + 1 + ... + 1) [there are still "x" terms in the parentheses]

2x = x

divide by x:

2 = 1