Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Another question.

  1. Jun 8, 2004 #1
    Hi again,

    I'm preparing for GRE Math. I regconize that Abstract Algebra is the most tough. Here is one of its problem, Any suggestion!!!.

    Thank you in advance.

    Let p and q be distinct primes. There is a proper subgroup J of the additive group of integers which contains exactly three elements

    of the set {p,p+q,pq, p^q,q^p}, which three elements are in J.

    A. pq, p^q, q^p
    B. p+q,pq, p^q
    C. p,p+q, pq
    D. p,p^q,q^p
    E. p, pq,p^q
  2. jcsd
  3. Jun 8, 2004 #2


    User Avatar
    Science Advisor
    Homework Helper

    So doesn't this mean that the group operation for J is regular addition? And since it is an additive group, it should satisfy:
    1. If A, B are in J, then A+B in J
    2. If A, B, C are in J, then (A+B)+C = A+(B+C)
    3. There is an I such that A+I = I+A = A
    4. There is an inverse, A' for each A such that A' + A = A + A' = I

    I've probably interpreted something wrong (or you haven't given enough information) because this doesn't seem possible. Perhaps it's not regular additions we should be looking at?
  4. Jun 8, 2004 #3
    Every non-trivial additive subgroup of the integers is generated by its least positive element. So J = {ma | m in Z} for some a. Out of the 5 elements in the given set, you need to choose a set of 3 all of which are multiples of the same number, and such that the other two elements are not multiples of this number.

    Note that p, pq, pq are all multiple of p.
    On the other hand, since p and q are relatively prime, p+q and qp are not multiples of p.

    Hence E is your answer.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook