How do you prove that CD/AB = DE/AE when Angle A = Angle D in the attached Diagram??
Here is the image
if angle A = angle D
what can u say about the triangles ABE and EDC?
what conclusion can u make?
Not sure I am wrong but here is my first thoughts
Angle AEB = Angle DEC
Therefore Angle ABE = Angle DCE
which means that the two triangles are congruant
This is my tought
u can get to say that those triangles are similar
so u can use the proportion law
and obtain the result
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