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  1. Apr 2, 2005 #1
    How do you prove that CD/AB = DE/AE when Angle A = Angle D in the attached Diagram??

    THanks
     

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    Last edited: Apr 2, 2005
  2. jcsd
  3. Apr 2, 2005 #2
    Here is the image
     

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  4. Apr 2, 2005 #3
    if angle A = angle D
    what can u say about the triangles ABE and EDC?
    what conclusion can u make?
     
  5. Apr 2, 2005 #4
    Not sure I am wrong but here is my first thoughts

    Angle AEB = Angle DEC

    Therefore Angle ABE = Angle DCE

    which means that the two triangles are congruant

    This is my tought
     
  6. Apr 2, 2005 #5
    u can get to say that those triangles are similar
    so u can use the proportion law
    and obtain the result
    ok?
     
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