- #1
dwn
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*****Please see 3rd post and ignore calculations on this one******
Please see image.
alpha = 1/2RC
omega = 1/√(LC)
iL(t) = e-αt(A1[\SUB]coswdt + A2sinωdt)
iL(0) = 5 ∴A1 = 5
Evaluating di/dt at t = 0 :
∴
I've messed up somewhere...not sure where though. Please help.
Homework Statement
Please see image.
Homework Equations
alpha = 1/2RC
omega = 1/√(LC)
iL(t) = e-αt(A1[\SUB]coswdt + A2sinωdt)
The Attempt at a Solution
iL(0) = 5 ∴A1 = 5
Code:
di/dt = e[SUP]-1.8541t[/SUP](-11sin(2.236t) + 2.236A[SUB]2[/SUB]cos(2.236t)) + 1.8541e[SUP]-1.8541t[/SUP](5cos(2.236t) + A[SUB]2[/SUB]sin(2.236t))
Evaluating di/dt at t = 0 :
Code:
2.236A[SUB]2[/SUB] + (1.8541 * 5) = 0
A[SUB]2[/SUB] = -4.146
∴
Code:
i[SUB]L[/SUB](t) = e[SUP]-1.8541t[/SUP](5cos(2.236t) - 4.146sin(2.236t))
I've messed up somewhere...not sure where though. Please help.
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