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Another Spring Question!

  1. Nov 7, 2005 #1
    An 8kg stone rests on a spring. the spring is compressed 10cm by the stone.

    What is the spriong constant?

    im not really sure how to start...Ws = -0.5kx^2

    im guessing that there must be a relationship between Wg and Ws obviously
    -Wg = Ws... but im not sure how to solve for Ws

    Can anyone help?
  2. jcsd
  3. Nov 7, 2005 #2
    F = mg = -kx
  4. Nov 7, 2005 #3
    b)the stone is pushed down an extra 30 cm. What is the elastic potential energy of the compressed spring just before the release?

    U = 0.5kd^2 d=distance compressed

    ...U = 6.27 x 10^-3 J

    ok....the next part asks for...

    what is the change in the gravitational potential energy of the stone-earth system when the stone moves from the release point to its max height

    so delta(U) = mg[delta(y)]

    how do i get the max height?
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