Okay - I thought that I figured this stuff out, but I didn't.(adsbygoogle = window.adsbygoogle || []).push({});

The Problem

When [tex]G(x, y, z) = (1-x^2-y^2)^{3/2}[/tex], and [tex]z = \sqrt{1-x^2-y^2}[/tex], evaluate the surface integral.

My Work

I keep trying this but I end up with the following integral that I cannot evaluate:

[tex]

\int_{-1}^{1} \!\!\! \int_{-\sqrt{1-y^2}}^{\sqrt{1-y^2}} (1-x^2-y^2)^{3/2}\sqrt{1+4x^2+4y^2} \,dx \,dy

[/tex].

Conversion to polar coordinates doesn't help much, either. How can I find this surface integral? (Ans:[itex]\frac{\pi}{2}[/itex])

Thanks!

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# Homework Help: Another Surface Integral

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