Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Another weird problem

  1. Jun 23, 2004 #1
    Thanks so very much with the help you gave me. I am truly grateful.
    By the way, here's another weird problem:
    A sample of with a mass of 250.g is heated to 130. degrees celcius, and dropped into 425g of H2O at 26.0 degrees C. The final temp. of the H2O is 38.4 degrees C. What is the specific heat capacity of the metal if 1.2 (10 exponent 3) Joules is lost to the enviroment.
    Once again, I am clueless!
     
  2. jcsd
  3. Jun 24, 2004 #2

    Gokul43201

    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    Heat lost by sample = heat gained by water + heat gained by surroundings
     
  4. Jun 30, 2004 #3
    specific heat = (4.18 x 425g of water x (38.4-26)+1.2)/(250x (130-38.4))
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Another weird problem
  1. Another universe (Replies: 1)

  2. Weird Reaction? (Replies: 11)

  3. Something Weird (Replies: 22)

Loading...